Good luck to everyone on the final exam! 

Here are the answers to most of the practice handouts I gave you in
class:

Practice exam question for Ch. 9: 
1) conservation of energy; fluid incompressible/continuity equation
2) f = 1 - rho_ice/rho_water = 0.90 and 0.92
3) if v goes up, then P goes down (Bernoulli) 

Practice exam question for Ch. 12, 13: 
a) 1.1 atm
b) 9.2 kg
c) 2075 J
d) 30.2 liter
e) 3735 J
f) 4980 J, some Q went into W

Practice exam question for Ch. 14: 
a) 3.34e5 kJ 
b) 8.8
c) 3.8e4 kJ
d) 440 W
e) -1.22e6 J/K 
f) +1.22e6 J/K 
g) eta < 8.8, W goes up, and delta S goes up in (f) 

Practice exam question for Ch. 26: 
1) see class notes for this example
2) 0.89c
3) 75 min

Ch. 14 - practice material: 
1) isobaric = horizontal line
2) isochoric = vertical line
3) isothermal = P = 1/V 
4) adiabatic = P = 1/V^{gamma} 

Activity - entropy flow:
delta S1 = +16 J/K 
delta S2 = 0
delta S3 = -16 J/K 
delta S4 = 0 
Plot - looks like rectangle, delta S_tot = 0, reversible
area enclosed = net work
heat leak - area changes 

Final Exam from 2001: 
I-1) rigid bottle, delta V = 0; full Carnot cycle, net work = 0
I-2) see me for diagram 
I-3) F_B = const., mass of displaced water doesnt change
I-4) 
a) 0-1 sec; 3.5-4.5 sec
b) +1.0 m/s^2
c) 0
d) 2.5-4.0 sec
I-5)
a) decrease, Q negative
b) entropy of air goes up (S cannot decrease)
II-1) 1 meter + 0.45 mm 
II-2) 
a) 1.01 sec
b) 29.7 kg m/s 
c) 1484 N 
II-3)
a) 1.21 M_E 
b) 5% larger
II-4) 
a) 9.8e3 Pa
b) 4.4 m/s
II-5) 
a) 122 K
b) 872 m/s CORRECTED  
II-6) 
a) 44%
b) 2273 J
c) 1273 J
II-7) 
a) 4.3 m
b) 2.3 sec/tick
III-1) 
a) W_AB = nRTln(V2/V1)
   W_BC = -P1(V2 - V1) 
   W_CA = 0
b) W = W_AB + W_AC 
c) Qin = W > 0 for AB; Qin = nRTln(V2/V1) 
III-2)
a) F,a = 0
b) W = F r theta = 5.5 J
c) KE = 11 J
d) 14 Nm 
e) 1.6 kg m^2
f) 8.75 rad/s^2
g) 0.43 sec
h) 3.76 rad/s
i) 11.3 J
j) 6.0 kg m/s
k) 8.2 rad/s